Cargo Handling Calculations
What you’ll learn
- Question (1)Cargo hold 10 x 8.5 x 4.2 m having dunnage spread regularly over the floor of the hold at a height of 20 cm. and the side battens are at 12.5 cm. from the shell plating on each side. the hold was loaded with 10000 boxes of lead each measuring 35 x 1 5 x 10 cm, and it was also loaded with 4000 barrels of paint each of 55 cm high and 30cm diameter; if the broken stowage for the barrels of paint in the hold was 5% of the barrels volume.Calculate the remaining hold volume and the number of cases knowing that S.F. of cases is 2 m3/ton and each 4 cases weigh one ton, “Assuming that there in no broken stowage for the box of lead”.
- A vessel has 8400 tones deadweight; she has onboard 750 tones of fuel, 250 tones of water, and 200 tones of stores. She has four holds of capacities as follows: No. 1 = 1500 m3 No. 2 = 2500 m3 No. 3 = 2500 m3 No. 4 = 1500 m3 It is required to load paper reels stowed at 0.5 m3/ton and butter cases stowed at 1.5 m3/ton Calculate how much of each commodity can be loaded, when the vessel is down to her marks and full to her capacity.
- A ship of 5000 tones deadweight has onboard, 200 tones of fuel– 90 tones of fresh water and 110 tones of stores The ship is loading 1000 tones cases of cans its stowage factor is 1.5 m3/t. If the cubic capacity of the ship holds is as follows: No. (1) 1800 m3 – No. (2) 3100 m3 – No. (3) 2800 m3 – No. (4) 2800 m3 No. (5) 1500 m3
- A vessel of 5080 tones deadweight has on board: 500 tones of fuel, 350 tones of water and 130 tones of stores She has four holds of capacities as follows: No. (1) 1320 m3 – No. (2) 1972 m3 – No. (3) 2050 m3 – No. (4) 1530 m3 It is required to load grain stowed at 1.45 m3/tone and bales of cotton stowed at 2.35 m3/tone. Calculate how much of each commodity can be loaded if the vessel is down to her marks and full to capacity, and how should the cargo be distributed?
- A hold of capacity 2060 m3 is to be filled with 1212 tones of Jute and gum. The bales of Jute measure (100 cm x 50 cm x 60 cm) and weighs 180 Kg each. The gum bales measures (100 cm x 50 cm x 80 cm) and weighs 250 Kg each. How many bales of each commodity should be stowed, allowing 5% for broken stowage?
- A ship 64 m. long and maximum beam 10 m. has a light draft of 1.5m and load draft of 4m.The block coefficient of fineness is 0.6 at the light draft and 0.75 at the load draft. She has onboard the following loads: Fuel: 100 tons Provisions 100 tons Fresh water 72 tons. General cargo 700.6 tones How many tones of cargo can be loaded to make the ship go down to her load line mark? Assuming the ship floats up right in salt water?
- A vessel of 4500 tones deadweight; has onboard 400 tones of fuel, 200 tones of water, and 200 tones of stores. She has four holds of capacity as follows: No. 1: 1300 cu.m. No. 2: 1880 cu.m No. 3: 1900 cu.m. No. 4: 1490 cu.m. It is required to load grain, stowed at 1.45 m3/ton, and bales of cotton stowed at 2.35 m3/ton. Calculate how much of each commodity can loaded, if the vessel will be down to her marks and full to her capacity.
- Cargo Ship with a dead weight of 6207 Tonnes has already onboard Fuel Oil and 22 T. Fresh water and 25 T, Provisions of the ship 330 has three holds have the following dimensions Hold No. 1: 12 m x 08 m x 04 m Hold No. 2: 10 m x 08 m x 04 m Hold No. 3: 09 m x 08 m x 04 m The holds has a spar ceiling on all four sides with a width of 12.5 cm each and a dunnage with a height of 10 cm. It is assigned to load coal to make the ship reach her maximum load line, calculate the quantity of coal that has to be loaded in each hold.
- ship with a dead weight of 5000 Tonnes has already onboard 200 T Fuel oil, 90 T. Fresh water, 110 T. Provisions and 1000 T. general cargo with a stowage factor of 1.5 m3/t, she has 5 holds with the following volume Hold No.1 = 1500 m3 Hold No.2 = 3100 m3 Hold No.3 = 2800 m3 Hold No.4 = 3100 m3 Hold No.5 = 1500 m3 Find the amount of the following cargo that can be loaded in the remaining holds space: Bales of Coffee with a stowage factor 2.8 m3/t Bales of Rice with a stowage factor 3.1 m3/t
Good internet connection and laptop or PC or phone .
- it is a live lecture via ICQ
- you can`t download the lecture .
we will solve all the above examples together on live lecture you have to add me via ICQ lecture will start in 14:00 GMT
this course is full of opportunities to apply your knowledge:
related for chief mate students in Jordan academy, cargo handling calculations in basic study in uk
Who this course is for:
for students study the basic study of maritime college
- for OOW have exam for cargo handling exam
- for chief mate preparation especially for students in Jordan academy
- Lectures 2
- Quizzes 0
- Duration 1.5 hours
- Skill level All levels
- Language English
- Students 221
- Assessments Yes